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Unformatted text preview: Magnetic Forces and Torques Review: Charged Particle in an external field : Straight wire of length L with current I in a uniform external field B: B v q F × = F I L B = × Note: L points in direction of positive current flow If B not uniform, and/or wire not straight: the force dF on a short segment of vector length dL is I I Segment of length dL The total force on the wire is: along wire F IdL B = × ∫ u uu u dF B dL dF = I dL x B Force on a currentcarrying wire (general case) Example 1 y x x x x x x x x x x I (uniform) R θ Find the force on: a) The straight wire b) The semicircular wire c) The whole circuit For (b): start with force dF due to an infinitesimal piece, and do the integral. B Solution Total magnetic force on the loop = 0 Proof: { } F IdL B I dL B = × ∫ = × ∫ uu uu But: for a closed loop, so F = 0 dL = ∫ uu Theorem : For any closed current loop in a uniform magnetic field, (if B is a constant vector) Torque:...
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This note was uploaded on 01/23/2011 for the course ENG 1D04 taught by Professor Done during the Spring '08 term at McMaster University.
 Spring '08
 DONE

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