PHYS126 Supplementary Notes 5

PHYS126 Supplementary Notes 5 - PHYS126 Supplementary Notes...

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Unformatted text preview: PHYS126 Supplementary Notes 5 1 Feel the number connecting the macroscopic world and microscopic world. How many C atoms are there in (a) 1 g of CO 2 (b) 1 mole of CH 4 (c) 1 k mole of C 2 H 6 a) 1g of CO 2 Number of moles of 1g CO 2 = 1/(12+2 x 16) = 1/44 Therefore, number of C atoms = A N x 1/44 = 1.37 x 10 22 b) 1 mole of CH 4 Number of C atoms = A N x 1 = 6.02 x 10 23 c) 1 k mole of C 2 H 6 Number of C atoms = A N x 2 x 1000 = 1.20 x 10 27 Where we know that, the Avogadro’s Number is 23 6.02 10 A N = × What does this number means? Let’s do some calculation, suppose we need 3 numbers to describe the 1 location of each atom, and every number will need a byte of computer memory to store them. Then we will need a total memory of about 12 1.8 10 TB × memory to store the location of these atoms ( 3 6 9 12 1 10 10 10 10 TB GB MB KB B = = = = ). Then now we want to tell somebody else about the location of these atoms, so we want to transport these data to him. Let us estimate how long will this so we want to transport these data to him....
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This note was uploaded on 03/31/2011 for the course PHY 126 taught by Professor Hobunchan during the Spring '11 term at HKUST.

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PHYS126 Supplementary Notes 5 - PHYS126 Supplementary Notes...

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