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Unformatted text preview: PHYS126 Supplementary Notes 6 1. De Broglieâ€™s Hypothesis hf E = and Î» h p = or Ï– = E and k p f = Ï€ 2 h = where s eV s J h . 10 14 . 4 . 10 63 . 6 15 34 Ã— = Ã— = Example: Find the wavelength of an electron with energy 2 E MeV = Hint: The De Broglie relation / h p Î» = is correct at all energies, but since the energy is relativistic at some case, you will have to use the relation ( 29 ( 29 2 2 2 E pc mc = + to find p . The energy is 2 E MeV = , and for electron 2 0.511 mc MeV = , so we have 1.934 PC MeV = So 15 4.14 10 h eV = Ã— , 13 6.42 10 m Î» = Ã— 2. Compton's Scattering ) cos 1 ( Î¸ Î» Î» + = c m h e Example: X rays of wavelength 0.2400nm are ComptonScattered, and the scattered beam is observed at an angle of 60 o C relative to the incident beam. Find a) the wavelength of the scattered X rays, b) the energy of the scattered Xray photons, c) the kinetic energy of the scattered electrons a) ) cos 1 ( Î¸ Î» Î» + = c m h e nm nm nm 2412 ....
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 Spring '11
 HoBunCHAN
 Physics, Energy, Photon, Bohr radius

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