hw2 solution

# hw2 solution - PHYS126 Spring 2011 Homework 2 Solution t...

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PHYS126 Spring 2011 Homework 2 Solution 1. (a) 2 2 2 2 2 2(500) 2.0833hr 100 1 500 1 500 ABA L t v c c = = = - - (b) 2 2 2 2 2 2(500) 2.0412hr 100 1 500 1 500 ACA L t v c c = = = - - 2. Consider the figure in Lecture 2 note slide #37, suppose there are two frames S and ' S ,where S moves with the three men and ' S moves with a velocity v relative to the men. Let L be the distance between adjacent men, 1 2 and t t be the time required for the light to arrive the man at the left and the right respectively in frame S ; 1 2 and t t be the time required for the light to arrive the man at the left and the right respectively in frame S . In Newtonian mechanics, speed of light can be varied by velocity vector addition. Then 1 2 1 2 1 1 2 2 : ': , L S t t c L vt L vt L L S t t t t c v c c v c = = - + = = = = - + Since 1 1 2 2 , t t t t = = , simultaneity is universal in Newtonian mechanics. In special relativity, speed of light is a constant in every inertial frame. Then

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## This note was uploaded on 03/31/2011 for the course PHY 126 taught by Professor Hobunchan during the Spring '11 term at HKUST.

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hw2 solution - PHYS126 Spring 2011 Homework 2 Solution t...

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