4 Solution Set 4 on chapters 8&amp;9

# 4 Solution Set 4 on chapters 8&amp;9 - 1 Chapter 8:...

This preview shows pages 1–3. Sign up to view the full content.

Chapter 8: Rotational Kinematics. Selected Conceptual Questions, pp.240. Problems pp. 241: # 13, 16, 25, 32, 40, 41, 52, 72 Chapter 9: Rotational Dynamics . Selected Conceptual Questions, pp.276. Problems pp. 277: # 5, 10, 12, 16, 19, 28, 37, 41, 46, 58, 72, 76 Chapter 8: Rotational Kinematics 13. REASONING AND SOLUTION The people meet at time t. At this time the magnitudes of their angular displacements must total 2 π rad. θ 1 + 2 = 2 rad Then ϖ 1 t + 2 t = 2 rad 3 3 1 2 2 rad 2 rad 1200 s 1.7 10 rad/s 3.4 10 rad/s t - - = = = + × + × 16. REASONING The time required for the bullet to travel the distance d is equal to the time required for the discs to undergo an angular displacement of 0.240 rad. The time can be found from Equation 8.2; once the time is known, the speed of the bullet can be found using Equation 2.2. SOLUTION From the definition of average angular velocity: t = the required time is 3 0.240 rad 2.53 10 s 95.0 rad/s t - ∆ = = = × Note that = because the angular speed is constant. The (constant) speed of the bullet can then be determined from the definition of average speed: 3 0.850 m 336 m/s 2.53 10 s x d v t t - = = = = × 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document