choi (kc24547) – HW04 – BERG – (56525)
1
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printout
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have
22
questions.
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before answering.
001
(part 1 of 4) 10.0 points
A Calculus student begins walking in a
straight line from the RLM building towards
the PCL Library. After
t
minutes his velocity
v
=
v
(
t
) is given (in multiples of 10 yards per
minute) by the function whose graph is
3
2
1
0
1
2
3
4
5
6
7
8
9
10
2
4
6
8
10

2
2
4
6

2
t
v
How far is the student from the RLM build
ing at time
t
= 4?
1.
dist = 60 yards
correct
2.
dist = 80 yards
3.
dist = 100 yards
4.
dist = 70 yards
5.
dist = 50 yards
Explanation:
The student is walking
towards the PCL
Library
whenever
v
(
t
)
>
0 and
towards RLM
whenever
v
(
t
)
<
0.
The distance he has
walked is given by 10 times the area between
the graph of
v
and the
t
axis since 1 unit is
equivalent to 10 yards.
Now at
t
= 4 this
area is 6 units, so the student has walked a
distance of 60 yards.
002
(part 2 of 4) 10.0 points
How far is the student from the RLM build
ing at time
t
= 6?
1.
dist = 110 yards
2.
dist = 160 yards
3.
dist = 140 yards
4.
dist = 130 yards
5.
dist = 120 yards
correct
Explanation:
The distance the student has walked is
given by the area between the graph of
v
and the
t
axis. Now at
t
= 6 this area is 12
units, so the student has walked a distance of
120 yards.
003
(part 3 of 4) 10.0 points
What is the total distance walked by the
student from time
t
= 0 to
t
= 10?
1.
dist = 190 yards
2.
dist = 210 yards
3.
dist = 200 yards
correct
4.
dist = 230 yards
5.
dist = 180 yards
Explanation:
The distance the student has walked is
given by the area between the graph of
v
and the
t
axis.
Now at
t
= 10 this area is
20 units (area is always positive remember),
so the student has walked a distance of 200
yards.
004
(part 4 of 4) 10.0 points
How far is the student from the RLM build
ing when he turns back?
1.
dist = 180 yards
correct
2.
dist = 220 yards
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choi (kc24547) – HW04 – BERG – (56525)
2
3.
dist = 150 yards
4.
dist = 170 yards
5.
dist = 200 yards
Explanation:
The student will turn back when his veloc
ity changes from postive to negative,
i.e.
, at
t
= 8. At this time he is 180 yards from the
RLM building.
keywords:
distance,
time, graph, velocity,
area
005
10.0 points
A Calculus student begins walking in a
straight line from the RLM building towards
the PCL Library. After
t
minutes his velocity
v
=
v
(
t
) is given (in multiples of 10 yards per
minute) by the function whose graph is
3
2
1
0
1
2
3
4
5
6
7
8
9
10
2
4
6
8
10

2
2
4
6

2
t
v
What is the total distance walked by the stu
dent from time
t
= 0 to
t
= 10?
1.
dist = 150 yards
correct
2.
dist = 160 yards
3.
dist = 140 yards
4.
dist = 180 yards
5.
dist = 170 yards
Explanation:
The distance the student has walked is
given by the area between the graph of
v
and the
t
axis. Now at
t
= 10 this area is 15
units (area is always positive remember), so
the student has walked a
distance of 150 yards
.
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 Spring '10
 ZHENG
 Calculus, Derivative, Fundamental Theorem Of Calculus, dx

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