MT 518 HW 3 Prob. Solutions

MT 518 HW 3 Prob. Solutions - Page 1 of 4 MT 518 Homework...

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Page 1 of 4 MT 518 Homework Problem Solutions – Lecture #3 3.1 What are the altitude and azimuth angles of the sun on the 21 st day of May at Newark, NJ at 11:00 am EST? What is the magnetic deviation of the azimuth angle at that location? sin α = sin L sin δ s + cos L cos δ s cos h s sin α s = cos δ s sin h s / cos α -------------------------------------------------------------------------------------------------------- Solar Declination, δ δ = 23.45 sin[360(284+n)/365] n = 141 (May 21) δ = 23.45 sin[360(284+141)/365] = 20.1º Solar Time, ST Solar Time (ST) = Local Std. Time (LST) + Equation of Time (E qt )/60 + (Long sm – Long local )/15 Equation of Time (for n = 141), E qt = 4.0 sin[π(n - 106)/59] Solar Time (ST) = 11.0 + {4.0sin [π(141 – 106)/59]}/60 + (75 – 74.2)/15 Note: sin angle in radians = 11.0 + 0.064 + 0.053 = 11.12 hrs. or 11:08 am Solar Hour Angle, h s h s = 15º x Hours from local solar noon = 15 x (12 – 11.12) = 13.2º --------------------------------------------------------------------------------------------------------
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MT 518 HW 3 Prob. Solutions - Page 1 of 4 MT 518 Homework...

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