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# 1M03 2009 ASSIGNMENT 3-2...

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View Results Name: SOO NAM Attempt: 2 / 3 Out of: 28 Started: February 22, 2009 6:11am Finished: February 22, 2009 6:45am Time spent: 33 min. 49 sec. Question 1 (1 point) A metal wire 2.24 mm in diameter is to offer a resistance of no more than 5.30 Ω . Given that the conductivity of this metal is 2.37 x 10 7 ( Ω -m) -1 , calculate the maximum wire length (in m). Use decimal notation, digits after decimal: 0 Student response: 495 m Correct answer: 495 m General feedback: This problem can be solved using an extension of Ohm's Law. For more information see page 612 of the text and equation 18.2. Score: 1 / 1 Question 2 (1 point) The typical electrical conductivity value/range for metals is: Student response: Correct Response Student Response Answer Choices a. 10 7 ( Ω -m) -1 b. 10 -20 to 10 -10 ( Ω -m) -1 c. 10 -6 to 10 4 ( Ω -m) -1 General feedback: Metals typically have electrical conductivities on the order of 10 7 ( Ω -m) -1 . See page 614 in the text. Score: 1 / 1 Question 3 (1 point) The energy corresponding to the highest filled electron state at 0 K is called the _____________ energy. Student response: No. Student response Grade Correct answer (Value) 1. Fermi 100% Answer evaluated by the formula. (100%) General feedback: See page 616 of the text for more information. Score: 1 / 1 Question 4 (1 point) When an electric field is applied, in which direction are the free electrons accelerated? Student response: Correct Response Student Response Answer Choices a. In the same direction as the electric field. b. In the direction opposite to that of the electric field. General feedback: When an electric field is applied, the free electrons are accelerated in the direction opposite to that of the electric field . See page 619 of the text. Score: 1 / 1 Question 5 (1 point) Estimate the electrical resistivity (in Ohm-m) of metal Y containing 1.38 at% of metal Z at 128°C, given the following material constants:

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Assume that all of the 1.38 at% of metal Z goes into solid solution in metal Y. Use scientific notation, significant figures in answer: 3 r 0 a A for one in the other (Omega-m) (Omega-m/°C) (Omega-m) 1.44 x 10 -8 6.40 x 10 -11 1.50 x 10 -6 Student response: 4.30e-8 Ohm-m Correct answer: 4.30E-8 (4.30 * 10 -8 ) Ohm-m General feedback: The total resistivity is equal to the sum of thermal, impurity, and deformation resistivity
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## This note was uploaded on 04/04/2011 for the course MATLS 1M03 taught by Professor Okon during the Spring '09 term at McMaster University.

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1M03 2009 ASSIGNMENT 3-2...

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