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# Lecture 21 - ENGR-1100 Introduction to Engineering Analysis...

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Lecture 21 Notes courtesy of: Prof. Yoav Peles ENGR-1100 Introduction to Engineering Analysis

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Homework Assignment (due next class) Problem 7-96 Problem 7-103 Problem 7-113
Lecture outline Machines

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Class Example: P7-89 A pin-connected system of bars supports a 300 lb load as shown in Fig. P7-89. Determine the reactions at supports A and B and the force exerted by the pin at C on member ACE.
Solution From a free-body diagram For the complete system: From a free-body diagram for pin F (note use of local coordinates): + F x = A x + B x = A x - 450 = 0 + M A = - B x (20) - 300 (30) = 0 B x = -450 lb = 450 lb A x = 450 lb = 450 lb + F y’ = T EF -300 sin 45 ° = 0 EF

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From a free-body diagram for bar ACE: + M C = -A y (10) + 450 (10) - 212.1 (10/cos 45 ° ) = 0 A y = 150.0 lb = 150.0 lb + F y = A y + C y - 212.1 sin 45 ° = 150.0 + C y - 212.1sin 45 ° = 0 C y = 0 + F x = C x + 450+212.1 cos 45 ° =0 C x = - 600 lb
From a free-body diagram For the complete system: + F y = B y + A y - 300 = B y + 150.0 - 300 = 0 B y = 150.0 lb = 150.0 lb A = = = 474.3 lb 2245 474 lb ( 29 ( 29 2 2 x y A A + ( 29 ( 29 2 2 450.0 150.0 + θ A = tan -1 = 18.434 ° A 2245 474 lb 18.43 ° 150.0 450.0

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Class assignment: Exercise set P7-110 A cylinder with a mass of 150 kg is supported by a two-bar

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Lecture 21 - ENGR-1100 Introduction to Engineering Analysis...

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