# Lecture 21 - ENGR-1100 Introduction to Engineering Analysis...

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Lecture 21 Notes courtesy of: Prof. Yoav Peles ENGR-1100 Introduction to Engineering Analysis

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Homework Assignment (due next class) Problem 7-96 Problem 7-103 Problem 7-113
Lecture outline Machines

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Class Example: P7-89 A pin-connected system of bars supports a 300 lb load as shown in Fig. P7-89. Determine the reactions at supports A and B and the force exerted by the pin at C on member ACE.
Solution From a free-body diagram For the complete system: From a free-body diagram for pin F (note use of local coordinates): + F x = A x + B x = A x - 450 = 0 + M A = - B x (20) - 300 (30) = 0 B x = -450 lb = 450 lb A x = 450 lb = 450 lb + F y’ = T EF -300 sin 45 ° = 0 EF

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From a free-body diagram for bar ACE: + M C = -A y (10) + 450 (10) - 212.1 (10/cos 45 ° ) = 0 A y = 150.0 lb = 150.0 lb + F y = A y + C y - 212.1 sin 45 ° = 150.0 + C y - 212.1sin 45 ° = 0 C y = 0 + F x = C x + 450+212.1 cos 45 ° =0 C x = - 600 lb
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## This note was uploaded on 04/04/2011 for the course ENGR 1100 taught by Professor Anderson during the Fall '06 term at Rensselaer Polytechnic Institute.

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Lecture 21 - ENGR-1100 Introduction to Engineering Analysis...

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