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Unformatted text preview: Give the equations of the crosssections of the function f ( x , y ) = y 2 + 1 when x = 1 and when y =1. This is a parabolic cylinder, whose equation is independent of x . Therefore, the equations of the two crosssections are x = 1 : f (1 , y ) = y 2 + 1 and y =1 : f ( x ,1) = 2 Note that the x = const . crosssections have all the same equations z = y 2 + 1, and f ( x ,1) = 2 is the horizontal line z = 2 in the y =1 plane....
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This note was uploaded on 04/04/2011 for the course MA 3160 taught by Professor Staff during the Spring '08 term at Michigan Technological University.
 Spring '08
 Staff
 Multivariable Calculus

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