This preview shows page 1. Sign up to view the full content.
Unformatted text preview: Give the equations of the cross-sections of the function f ( x , y ) = y 2 + 1 when x = 1 and when y =-1. This is a parabolic cylinder, whose equation is independent of x . Therefore, the equations of the two cross-sections are x = 1 : f (1 , y ) = y 2 + 1 and y =-1 : f ( x ,-1) = 2 Note that the x = const . cross-sections have all the same equations z = y 2 + 1, and f ( x ,-1) = 2 is the horizontal line z = 2 in the y =-1 plane....
View Full Document
This note was uploaded on 04/04/2011 for the course MA 3160 taught by Professor Staff during the Spring '08 term at Michigan Technological University.
- Spring '08
- Multivariable Calculus