Lecture 9

Lecture 9 - Reducing C requires high energy electrons: H 2...

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Unformatted text preview: Reducing C requires high energy electrons: H 2 (-.42 V) NADPH (-.35 V) or reduced Ferredoxin ( -0.39 V). P+ NADPH P+ NADPH Note the two different types of oxidase: dissimilatory and assmilatory H + H + H + H + H + H + H + H + H + H + H + H + H + H + H + H + NADP NADPH Reverse e- fow Reverse electron fow runs an ETC in reverse: the proton gradient is used to add energy to an e- Photosystem I is a great source of high energy e- (PSII) (PSI) (PSI) Photosystem II works, but requires reverse e- fow. (PSII) (PSI) (PSI) What happens if you make a cyclic pathway into a linear pathway? Chl Chl Chl* NADPH CH 2 O This is photolithoautotrophy S 2 O 3 The electron can come from an inorganic e- donor: sulfur, H2S, Fe, As... photosystem II So, anything that can give electrons to photosystem II can be used for autotrophy. “Anoxygenic photosynthesis” is found in diverse members of the Bacteria. Water is the worst possible e- donor...unless its e- get a huge boost.its e- get a huge boost....
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This note was uploaded on 04/05/2011 for the course MIC 102 taught by Professor Appleman during the Fall '08 term at UC Davis.

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Lecture 9 - Reducing C requires high energy electrons: H 2...

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