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q1_sol - 0 Physics 133 9:30 section Autumn 2010 Name...

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Unformatted text preview: 0. Physics 133, 9:30 section, Autumn 2010 Name g [24% {O )1} Recitation Instructor (circle one): Albert» Dainton Patton Schmidt Smith Zizka QUIZ #1 September 30, 2010 ' 25 points, 18 minutes SCORE For the problems below, use the class standard form for simple harmonic motion: x = xm cos(cot+¢°). x (“5:0 (1) 12 points. (a) What is the maximum velocity for the oscillator 19 cm" described by the graph? (b) What is a possible value for its phase constant? (For both parts, make sure you look carefully at the graph.) 49ng T54 we]: 73 7‘0 56% 69%.?“ ‘ i=0 .4 a PM Mama 034 (a: 2’”: 1-; 32: remember ice'flg); 92" TA“; am 56651;) Mir-4f; 01042 «FOE/fl T (‘0 .3‘tS avg/es a? 3% 5106105. é halo {0:09 05g,n=>‘/fi‘..t)l Va" me'(JI)‘(.)?m) 0“ “i s ”I“ °° fl 1 ( J 33: iga Mw9"L remember flart we, neeJ -/o céeck 14c 5/}; <31Z ‘U€(oc) ha. 523 so $3139, A; {Gas “67L/ (2) 5 points. At t = 0, an oscillator is found to hav kinetic and potential energies of K =4.5 J and U = 7.5 J. What is a possible value for the phase constant? l4 2 (3’1. 311, ,L 1 1' zé “WA/am : $33- KO 92M[V(° —- zmw X" $127 a (A, 0 70§J , z “(0} - ékédOJJ '2 Elk Km’zCOSQé ta” éri 3 ate .K/— {“4“} 2939371 w: 5“ Hue 0L ékxm‘cos‘qflg kw“. %:.66‘nm/ {Mt (w 2:— M 25 se (3) 8 points. The spring force acting on a 20 g particle undergoing simple harmonic motion is given by: Fx(t) = (20 N) cos(8.0 t + n/Z). What is the amplitude of the motion? 2L0 M i/Z mks: . ...
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