hw04_sol - 1. (a) From Fig. 33-2 we find the smaller...

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1. (a) From Fig. 33-2 we find the smaller wavelength in question to be about 515 nm. (b) Similarly, the larger wavelength is approximately 610 nm. (c) From Fig. 33-2 the wavelength at which the eye is most sensitive is about 555 nm. (d) Using the result in (c), we have 8 14 3.00 10 m/s 5.41 10 Hz 555 nm c f ! " " " ! # . (e) The period is T = 1/ f = (5.41 ! 10 14 Hz) –1 = 1.85 ! 10 –15 s.
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13. (a) The magnetic field amplitude of the wave is B E c m m ! ! " ! " # 20 2998 10 67 10 8 9 . . . V/ m m/s T. (b) The intensity is I E c m ! ! " $ " ! " # # 2 0 2 7 8 3 2 20 2 4 10 2998 10 53 10 % . . . . V/ m T m/A m/s W/ m 2 b g c hc h (c) The power of the source is ’ ( ’ ( 2 2 3 2 avg 4 4 10m 5.3 10 W/m 6.7 W. P r I # ! ! " !
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18. From the equation immediately preceding Eq. 33-12, we see that the maximum value of ! B/ ! t is " B m . We can relate B m to the intensity: 0 2 m m c I E B c c # $ $ , and relate the intensity to the power P (and distance r ) using Eq. 33-27. Finally, we relate
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This note was uploaded on 04/05/2011 for the course PHYSICS 133 taught by Professor Steigman during the Fall '09 term at Ohio State.

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hw04_sol - 1. (a) From Fig. 33-2 we find the smaller...

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