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hw06_sol - 10(a We note that ray 1 travels an extra...

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10. (a) We note that ray 1 travels an extra distance 4 L more than ray 2. To get the least possible L which will result in destructive interference, we set this extra distance equal to half of a wavelength: 420.0 nm 4 52.50 nm 2 8 8 L L λ λ = = = = . (b) The next case occurs when that extra distance is set equal to 3 2 λ . The result is 3 3(420.0 nm) 157.5 nm 8 8 L λ = = = .
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