ma Quiz 9

# Ma Quiz 9 - minute per gram of carbon The half-life of 14 C is 5715 years Calculate the age of the shroud(3pts k =.693/t 1/2 =.693/5715 yr = 1.213

This preview shows pages 1–2. Sign up to view the full content.

Chemistry 106 Recitation 3- 24 1. Write out the balanced reactions for the following and state the type of decay: (2pts) a. 180 Au to 180 Pt 180 Au + -1 e h 180 Pt b. 56 Co to 56 Ni 56 Co h 1 e + 56 Ni 2. 226 Rn decays twice by α particle emission followed by positron emission and finally electron capture twice. Write out the reaction and what is the resulting element? (2pt) 226 / 86 Rn h 4 / 2 He + 222 / 84 Po 222 / 84 Po h 4 / 2 He + 218 / 82 Pb 218 / 82 Pb h 218 / 81 Tl + 1 e 218 / 81 Tl + -1 e h 218 / 80 Hg 218 / 80 Hg + -1 e h 218 / 79 Au 3. Predict the type of decay for each atom (1pts) a. 40 K . . . this is about stable it may undergo beta b. 238 U . . . alpha decay 4. The cloth of a shroud from around a mummy is found to have a 14 C activity of 9.7 disintegrations per minute per gram of carbon as compared with living organisms that undergo 16.3 disintegrations per

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: minute per gram of carbon. The half-life of 14 C is 5715 years. Calculate the age of the shroud. (3pts) k = .693/t 1/2 = .693/5715 yr = 1.213 e-4 per year t= -1 [ln(N t /N o )] = -1 x ln(9.7/16.3) = 4.28 e3 years k 1.213 e-4 yr-1 5. Describe the process of fission and summarize the main conditions required. (2 pts) Questions 21. 40-21.42 in your book would be great additional practice . . . hint hint Chemistry 106 Recitation 3-24 Fission is the splitting on an atom releasing energy. A fissile isotope and a low energy neutron that can be absorbed causing the spontaneous fission of the nucleus are required for the fission process. Questions 21. 40-21.42 in your book would be great additional practice . . . hint hint...
View Full Document

## This note was uploaded on 04/07/2011 for the course CHEM 106 taught by Professor Herron,s during the Winter '08 term at BYU.

### Page1 / 2

Ma Quiz 9 - minute per gram of carbon The half-life of 14 C is 5715 years Calculate the age of the shroud(3pts k =.693/t 1/2 =.693/5715 yr = 1.213

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online