ma Quiz 9

Ma Quiz 9 - minute per gram of carbon The half-life of 14 C is 5715 years Calculate the age of the shroud(3pts k =.693/t 1/2 =.693/5715 yr = 1.213

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Chemistry 106 Recitation 3- 24 1. Write out the balanced reactions for the following and state the type of decay: (2pts) a. 180 Au to 180 Pt 180 Au + -1 e h 180 Pt b. 56 Co to 56 Ni 56 Co h 1 e + 56 Ni 2. 226 Rn decays twice by α particle emission followed by positron emission and finally electron capture twice. Write out the reaction and what is the resulting element? (2pt) 226 / 86 Rn h 4 / 2 He + 222 / 84 Po 222 / 84 Po h 4 / 2 He + 218 / 82 Pb 218 / 82 Pb h 218 / 81 Tl + 1 e 218 / 81 Tl + -1 e h 218 / 80 Hg 218 / 80 Hg + -1 e h 218 / 79 Au 3. Predict the type of decay for each atom (1pts) a. 40 K . . . this is about stable it may undergo beta b. 238 U . . . alpha decay 4. The cloth of a shroud from around a mummy is found to have a 14 C activity of 9.7 disintegrations per minute per gram of carbon as compared with living organisms that undergo 16.3 disintegrations per
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Unformatted text preview: minute per gram of carbon. The half-life of 14 C is 5715 years. Calculate the age of the shroud. (3pts) k = .693/t 1/2 = .693/5715 yr = 1.213 e-4 per year t= -1 [ln(N t /N o )] = -1 x ln(9.7/16.3) = 4.28 e3 years k 1.213 e-4 yr-1 5. Describe the process of fission and summarize the main conditions required. (2 pts) Questions 21. 40-21.42 in your book would be great additional practice . . . hint hint Chemistry 106 Recitation 3-24 Fission is the splitting on an atom releasing energy. A fissile isotope and a low energy neutron that can be absorbed causing the spontaneous fission of the nucleus are required for the fission process. Questions 21. 40-21.42 in your book would be great additional practice . . . hint hint...
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This note was uploaded on 04/07/2011 for the course CHEM 106 taught by Professor Herron,s during the Winter '08 term at BYU.

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Ma Quiz 9 - minute per gram of carbon The half-life of 14 C is 5715 years Calculate the age of the shroud(3pts k =.693/t 1/2 =.693/5715 yr = 1.213

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