MCB121 PMT2 Winter 2011-key

MCB121 PMT2 Winter 2011-key - Name MCB121 Spring 2010 Page...

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Name_______________________________ MCB121 Spring 2010 Page of 10 1 MCB121 Second Midterm, Feb 18, 2010 Instructions: • There are nine pages in this exam including the cover sheet, please count them before you start to make sure all are present. Write your name on each page of the exam. • Write your answers in the space provided below each question. If you need more space use the back of the page and indicate clearly that you have continued your answer on the back. Do not use additional paper. Amino acid Abbreviations Amino acid Abbreviations Alanine Ala A Leucine Leu L Arginine Arg R Lysine Lys K Asparagine Asn N Methionine Met M Aspartic acid Asp D Phenylalanine Phe F Cysteine Cys C Proline Pro P Glutamine Gln Q Serine Ser S Glutamic Acid Glu E Threonine Thr T Glycine Gly G Tryptophan Trp W Histidine His H Tyrosine Tyr Y Isoleucine Ile I Valine Val V 1. (20 points) For each of the following, write what kind of organism (yeast, mammals, or plants – more than one if more than one applies) it has utility for in eukaryotic transformation and briefly describe how it is useful. (5 points each) a) Gene replacement – Yeast. Positive and negative selection can be used to replace any gene in yeast with a copy containing any engineered alteration. b) Embryonic stem cells – Mammalian transformation. Following transformation, these pleuripotent stem cells can be injected into a mouse embryo. The resulting chimeric progeny can give rise to fully transgenic animals following sexual reproduction. c) Agrobacerium tumefaciens – Plant transformation. Can transfer a region of DNA into a plant cell. DNA can be engineered so that desired genes are transferred. d) Retroviral vector – Mammalian transformation. RNA genome is transferred into an animal cell and converted into dsDNA that inserts into the genome. The virus can be engineered to insert desired genes.
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Name_______________________________ MCB121 Spring 2010 Page of 10 2 2. (12 points) Mark the single most correct answer to each of the following. a) (4) Which of the following is NOT a feature of a human cDNA library? X The absence of introns allows for easy identification of critical promoter sequences in the clones. Promoter sequences would not be in a cDNA library. Reverse transcriptase is necessary for library construction. Libraries made from different organs of the same individual would contain significantly different populations of clones. It can include clones representing the population of mRNA in a cell or tissue sample. When inserted into an appropriate expression vector it could be effectively screened in bacteria using an activity assay for a particular human enzyme. b) (4) A transient expression analysis of a cloned gene in cultured mouse cells: Works best if telomeres are included in the transforming DNA. X Requires a promoter that functions in mouse cells to be effective.
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MCB121 PMT2 Winter 2011-key - Name MCB121 Spring 2010 Page...

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