Lab3hydrate - Moles of CuSO 4 19.18/159.61=.1202 Ratio of...

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Brian Turner Lab 3 Hydrate Formula In this experiment I will use 30 grams of Copper (II) Sulfate (CuSO 4 ) Initial Weight: 30g of CuSO 4 80g (CuSO 4 + Beaker) Final Weight: 19.18g of CuSO 4 69.18 (CuSO 4 + Beaker) Weight of Water Driven Off: 30g -19.18g = 10.82g or 80g - 69.18g = 10.82 Moles of Water Loss: 10.82/18.06= .6006
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Unformatted text preview: Moles of CuSO 4 : 19.18/159.61= .1202 Ratio of Moles of Water Loss to Moles of CuSO4: .6006/.1202= 4.997, rounds up to 5 X = moles of water loss/moles of CuSO4 Given that hydrate is CuSO 4 (XH 2 O) Formula of hydrate= CuSO 4 (5H 2 O) or CuSO 4 . 5H 2 O...
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