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Unformatted text preview: sanchez (ds28677) – homework 32 – Turner – (58220) 1 This printout should have 16 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points A traveling wave propagates according to the expression y = (2 . 12 cm) sin bracketleftBig (1 . 23 cm − 1 ) x (3 . 79 s − 1 ) t bracketrightBig , where x is in centimeters, and t is in seconds. Find the amplitude of the wave. Correct answer: 2 . 12 cm. Explanation: Let : A = 2 . 12 cm . Given a wave y = A sin( k x ω t ), the ampli tude of the wave is A = 2 . 12 cm . 002 (part 2 of 4) 10.0 points Determine the wavelength of the wave. Correct answer: 5 . 10828 cm. Explanation: Let : k = 1 . 23 cm − 1 . The angular wave number of the wave is k , so λ = 2 π k = 2 π 1 . 23 cm − 1 = 5 . 10828 cm . 003 (part 3 of 4) 10.0 points Determine the frequency of the wave. Correct answer: 0 . 603197 Hz. Explanation: Let : ω = 3 . 79 s − 1 . The angular frequency of the wave is ω , so f = ω 2 π = 3 . 79 s − 1 2 π = . 603197 Hz . 004 (part 4 of 4) 10.0 points Determine the period of the wave. Correct answer: 1 . 65783 s. Explanation: The period of the wave is T = 1 f = 1 . 603197 Hz = 1 . 65783 s . 005 10.0 points A wave on a string is described by the wave function y = (0 . 1 m) sin[(0 . 5 rad / m) x (20 rad / s) t ] Determine the frequency of oscillation of a particular point at x = 2 . 0 m. Correct answer: 3 . 1831 Hz. Explanation: Let : ω = 20 rad / s . In fact, when a wave with frequency f trav els along a string, any point of the string has the same oscillation frequency f . In this case, f = ω 2 π = 20 rad / s 2 π = 3 . 1831 Hz keywords: 006 (part 1 of 2) 10.0 points A steel piano wire is 0 . 7 m long and has a mass of 80 g. It is stretched with a tension of 300 N. What is the speed of transverse waves on the wire?...
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 Spring '08
 Turner
 Physics, Work, Correct Answer, Sanchez

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