Solution_Set_01 - which is at 8:02 pm. 9. a) Yes, if you...

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SOLUTION SET 1 Physics 2022 1a. d = 1.496 x 10 8 km / 9.46 x 10 12 km/ly = 1.58 x 10 -5 ly 1b. d = 1.496 x 10 8 km / [ (606,265 AU/pc) (1.5 x 10 8 km/AU)] = 4.85 x 10 -6 pc 1c. No too small 2. d = c t = (3 x 10 5 km/s) (4 hr) (3600 s/hr) = 4.3 x 10 9 km 3a. d = (3.50 pc) (3.09 x 10 13 km) / (1 pc) = 1.08 x 10 14 km 3b. d = (3.50 pc) (3.26 ly/pc) = 11.4 ly so it takes 11.4 years 4. t = 14 x 10 9 years x 365.25 days/year x 24 hr/day x 60 min/hr x 60 sec/min = 4.42 x 10 17 seconds 5. It is the number of arcseconds in one radian (= 57.29 degrees). 6. a) D = d sin θ d = 0.026/2 m / sin (0.5 deg) = 1.5 m b) D = d sin θ d = 0.026/2 m / sin (0.5 deg / 60) = 89 m c) D = d sin θ d = 0.026/2 m / sin (0.5 deg / 3600) = 5360 m 7. a) θ = 1.4 deg (x 60 arcmin/deg) = 84 arcmin b) θ = 1.4 deg (x 60 arcmin/deg x 60 arcsec/arcmin) = 5040 arcsec 8. It rises 4 minutes earlier each day, so in one week it rises 7 x 4 = 28 minutes sooner,
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Unformatted text preview: which is at 8:02 pm. 9. a) Yes, if you are standing at one of the poles, all of the stars are circumpolar. b) Yes, if you are standing on the equator, none of the stars are circumpolar. 10. Latitude = 40 o N Sun is at -23.5 o N Distance from the zenith is 40.0 – (-23.5) = 63.5 o Altitude from the horizon is 90.0 – 63.5 = 26.5 o 11. At 19 o north latitude the Sun is on the zenith at midday twice during the year because Mumbai’s latitude is less than 23.5 o . 12. Star 1 RA = 8 hr 00 m 00 s Dec = +00 o 00’ 00” Star 2 RA = 11 hr 20 m 00 s Dec = +00 o 00’ 00” The difference in RA = 3hr 20m = 3.33hr (3.33 hr ) / (24 hr ) = Angle / 360 o Angle = 50 o Problems 1a, 3a, 4, 6c, 9a, and 11 are worth 1 point each. Problem 12 is worth 2 points....
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This note was uploaded on 04/07/2011 for the course PHYS 2022 taught by Professor Sowell during the Spring '11 term at Georgia Institute of Technology.

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Solution_Set_01 - which is at 8:02 pm. 9. a) Yes, if you...

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