This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: λ = 600 nm = 600 x 109 m then α = (1.25 x 10 6 )(600 x 109 ) = 0.75 arcsec 7a. D = d tan α = (6.28 x 10 8 km) tan [(0.1 arcsec) / (60 x 60)] = 304.5 km Hubble’s resolution on Io. 7b. D = d tan α = (3.844 x 10 5 km) tan [(1.0 arcmin) / (60)] = 111.8 km Human eye’s resolution on the Moon. 8a. D = d tan α = (7 x 10 7 ly) tan ( 0.1 / 3600 ) = 34 ly 8b. d = D / tan α = (1.8 x 105 km) / tan ( 0.1 / 3600 ) = 37 km 9. α = 250,000 λ / D λ 1 = 5 x 107 m D 1 = 4 m λ 2 = 104 m λ 1 / D 1 = λ 2 / D 2 D 2 = D 1 λ 2 / λ 1 = (4 m) (104 m) / (5 x 107 m) = 800 m 10. α = 250,000 λ / D 103 arcsec = 250,000 (550 x 109 m) / D D = 250,000 (550 x 109 m) / (103 arcsec) D = 137.5 m Problems 2, 3, 6a, 7a, and 8b are each worth 1 point. Problem 9 is worth 2 points....
View
Full
Document
This note was uploaded on 04/07/2011 for the course PHYS 2022 taught by Professor Sowell during the Spring '11 term at Georgia Institute of Technology.
 Spring '11
 sowell
 Physics

Click to edit the document details