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Unformatted text preview: When this occurs, we need to balance the numbers of O and H atoms that appear in H + , OH-and H 2 O species in the reaction. For example, in acid MnO 4- Mn 2+ is a 5 electron process in base MnO 4- MnO 2 is a 3 electron process Note the change in oxidation number means a different equivalent weight for the MnO 4-depending on the reaction. So we need to add an additional step in balancing redox reactions: e/f. Rules for acid solution: balance O by adding H 2 O, then balance H by adding H + Rules for basic solution: for each O, add two OH-to side needing O and one H 2 O to other side for each H + , add one H 2 O to side needing H + and one OH-to other side. [Alternatively for base simply first balance in acid, then add enough OH-to neutralize all the H + followed by cancelling out any H 2 O that appears on each side of the reaction.]...
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