{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# 1-1 - Create assignment 00224 Homework 1 Jan 10 at 4:03 pm...

This preview shows pages 1–2. Sign up to view the full content.

Create assignment, 00224, Homework 1, Jan 10 at 4:03 pm 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Gravity on a New Planet 13:05, trigonometry, numeric, > 1 min, nor- mal. 001 Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 0 . 7 m and finds that it makes 120 com- plete oscillations in 446 s. The amplitude of the oscillations is very small compared to the pendulum’s length. What is the gravitational acceleration on the surface of this planet? Correct answer: 2 . 00056 m / s 2 . Explanation: Basic Concept A simple pendulum oscil- lating with small amplitude has period T = 2 π s g where is the pendulum’s length and g is the gravitational acceleration at the pendulum’s location. The pendulum in question made n = 120 complete oscillations in time t = 446 s, which implies the period of T = t n . Thus t n = 2 π s g t 2 n π = s g t 2 4 n 2 π 2 = g g = 4 n 2 π 2 t 2 Thus the planet’s surface gravity is g = 4 n 2 π 2 t 2 = 2 . 00056 m / s 2 .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 4

1-1 - Create assignment 00224 Homework 1 Jan 10 at 4:03 pm...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online