1-9 - Create assignment, 00224, Homework 9, Apr 08 at 6:09...

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Unformatted text preview: Create assignment, 00224, Homework 9, Apr 08 at 6:09 pm 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. Hinged Mirrors 01 35:04, highSchool, numeric, > 1 min, wording- variable. 001 The reflecting surfaces of two intersecting flat mirrors are at an angle of 56 , as shown in the figure. A light ray strikes the horizontal mirror at an angle of 53 with respect to the mirrors surface. 56 53 Figure is not drawn to scale. Calculate the angle . Correct answer: 68 . Explanation: Basic Concept: incident = reflected Solution: 1 2 Figure is to scale. The sum of the angles in a triangle is 180 . In the triangle on the left we have angles , 180 - 1 2 , and 180 - 2 2 , so 180 = + 180 - 1 2 + 180 - 2 2 , or 1 + 2 = 2 . (1) In the triangle on the right we have angles 1 , 2 , and . 180 = 1 + 2 + , so 1 + 2 = 180 - . (2) Combining Eq. 1 and 2, we have = 180 - 2 = 180 - 2(56 ) = 68 . As a matter of interest, in the upper-half of the figure the angles (clockwise) in the triangles from left to right are 37 , 37 , and 106 ; 74 , 34 , and 72 ; 108 , 19 , and 53 ; 127 , 19 , and 34 ; and in the lower-half of the figure the angles (counter-clockwise) in the triangles from left to right are 19 , 19 , and 142 ; 38 , 34 , and 108 ; 72 , 37 , and 71 ; 109 , 37 , and 34 . keywords: Perpendicular Mirrors 35:04, trigonometry, numeric, > 1 min, nor- mal. 002 Consider the case in which light ray A is in- cident on mirror 1 , as shown in the figure. The reflected ray is incident on mirror 2 and subsequently reflected as ray B. Let the an- gle of incidence (with respect to the normal) Create assignment, 00224, Homework 9, Apr 08 at 6:09 pm 2 on mirror 1 be A = 53 and the point of incidence be located 20 cm from the edge of contact between the two mirrors....
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1-9 - Create assignment, 00224, Homework 9, Apr 08 at 6:09...

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