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Unformatted text preview: Version 001 Quiz 20 sizemore (22956) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. Bar Moving in a Field 001 (part 1 of 2) 10.0 points A straight rod moves along parallel conduct- ing rails, as shown below. The rails are con- nected at the left side through a resistor so that the rod and rails form a closed rectangu- lar loop. A uniform field perpendicular to the movement of the rod exists throughout the region. Assume the rod remains in contact with the rails as it moves. The rod experiences no friction or air drag. The rails and rod have negligible resistance. 7 . 1g 9 . 5 3 . 8 T 3 . 8 T . 32A . 79m At what speed should the rod be moving to produce the downward current in the resistor? Correct answer: 1 . 01266 m / s. Explanation: Let : I = 0 . 32 A , = 0 . 79 m , m = 7 . 1 g , R = 9 . 5 , and B = 3 . 8 T . m R B B I From Ohms Law, the emf inside the loop is E = I R . and the motional emf is E = B v . Thus the velocity of the rod is v = E B = I R B = (0 . 32 A) (9 . 5 ) (3 . 8 T) (0 . 79 m) = 1 . 01266 m / s . 002 (part 2 of 2) 10.0 points The rod is 1. moving to the left. correct 2. moving to the right....
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This note was uploaded on 04/08/2011 for the course PHYS 1402 taught by Professor Avram during the Spring '10 term at Austin Community College.
- Spring '10