EAS208_L28_033011

EAS208_L28_033011 - ' \OMGV' Make“ A’B M P pvoblelvu...

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Unformatted text preview: ' \OMGV' Make“ A’B M P pvoblelvu humus 2f MuUcfig‘e maze 3¢6§Qg Mambzr A B 1? =1? -‘ .- 3 A+WA3xer a :61 d. " “ -" "‘ s A + «Aexrm 4. mm x(wA8xrB/A\ I: .. “A3: at; ‘ SIMK‘OW Ve\o¢.i b3 8’ O-ccdtvahou equa‘kok: [)qu For flair) 504m; BL a. Q a \Kduég Coks’cwduis (udzwuh risiJ Ladies and supports Rolling Wheel — Revisited A wheel of radius R is rolling along at a constant speed v without slipping. What is the angular speed? What is the velocity of point B on the rim at the instant shown? Path of a point on the outer circumference of a wheel rolling without slippage Parametric form x (t) = R cos (—m) + vt Motion ofA y(t) = Rsin(—a)t) + R v 2 (0R Cycloid fl/ V\ a a JVAZV ground =6 Tn‘mg, AQVIIVQ Eve, “to (:\V\é VQKOCJ" .‘ “d35- : VX :‘ WQSIW<”W£}‘FV dt : V[1,¥ SMQWME KMMJA Oufe V’X @Vg / Wig JED iav’ml 3%:Vb:pw(2gos<~wt\% V><*:.c> :«~\/CO.S('WJ2\ m£:/«%+7m“ Acadamb'oms 5 (fig, ; ow : 4&9 (ad’th V :o (w a . (5L (Mt: 3;; +TTW 2’. A 2 C13 2: ~00 QS‘V‘<‘Wfl Lon («:01MZ WMQM \ldogt'Jc/J COMQOKQKJU Vkia 8v V530 I amen pom/Gt /?‘\ fouohag SVO‘AL‘C‘W Wka’: (we HM. correggométkj QQLQJQWQJUOVU 7 1 Lqi wit 2?: «kl’WM W, 0 do wafirO (its: ufli CM 1. UIRA ' Accelerating Wheel A car has a forward acceleration l’ . a = 12% without slipping its 2417! diameter wheels. Determine the velocity v of the car when a point P on the wheel in the position shown will have zero horizontal acceleration. but“kou+ V5'WR Exam“ P a (1': ~ol a " “ mpx: m A— «(ml-(c w 1. cu'fl' 5° p, MI Hunt/I") '— gamma» kvth—sggels/ p / ...
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EAS208_L28_033011 - ' \OMGV' Make“ A’B M P pvoblelvu...

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