142 Ch 13 Kinetics - Chemistry 142 Chapter 13 Chemical...

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4/9/11 Chemistry 142 Chapter 13: Chemical
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4/9/11 Chapter 13 Examples – Rate Tro, Chemistry: A 22 at t = 0 [A] = 8 [B] = 8 [C] = 0 at t = 0 [X] = 8 [Y] = 8 [Z] = 0 at t = 16 [A] = 4 [B] = 4 [C] = 4 at t = 16 [X] = 7 [Y] = 7 [Z] = 1
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4/9/11 Concentration as a function of time
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4/9/11 Continuous Monitoring Sampling Tro, Chemistry: A 55
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4/9/11 First Order Reactions Tro, Chemistry: A 66 ln[A] 0 ln[A ] tim e slope = k
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4/9/11 Tro, Chemistry: A 77 Rate Data for C4H9Cl (aq) + H2O (l) Time (sec) [C4H9Cl], M 0.0 0.1000 50.0 0.0905 100.0 0.0820 150.0 0.0741 200.0 0.0671 300.0 0.0549 400.0 0.0448 500.0 0.0368 800.0 0.0200 10000.0 0.0000
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4/9/11 Tro, Chemistry: A 88 C4H9Cl (aq) + H2O (l) & C4H9OH (aq) + 2 HCl (aq) Concentration vs. Time for the Hydrolysis of C 4 H 9 Cl 0 0.02 0.04 0.06 0.08 0.1 0.12 0 200 400 600 800 1000 time, (s) concentration, (M)
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4/9/11 Tro, Chemistry: A 99 C4H9Cl (aq) + H2O (l) & C4H9OH (aq) + 2 HCl (aq) Rate vs. Time for Hydrolysis of C 4 H 9 Cl 0.0E+00 5.0E-05 1.0E-04 1.5E-04 2.0E-04 2.5E-04 0 100 200 300 400 500 600 700 800 time, (s) Rate, (M/s)
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4/9/11 Tro, Chemistry: A 1010 C4H9Cl (aq) + H2O (l) & C4H9OH (aq) + 2 HCl (aq) LN([C 4 H 9 Cl]) vs. Time for Hydrolysis of C 4 H 9 Cl y = -2.01E-03x - 2.30E+00 -4.5 -4 -3.5 -3 -2.5 -2 -1.5 -1 -0.5 0 0 100 200 300 400 500 600 700 800 time, (s) LN(concentration) slope = -2.01 x 10-3 k = 2.01 x 10-3 s-1 s 345 s 10 01 . 2 693 . 0 693 . 0 t 1 - 3 2 1 = × = = - k
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4/9/11 Chapter 13 – Examples Reaction Order Time (s) [N2O5] (mol/ L) 0 0.100 50 0.0707 100 0.0500 200 0.0250 300 0.0125 400 0.00625 Using the data below verify that the decomposition of dinitrogen pentaoxide is first order and calculate the value of the rate constant, where rate = -Δ[N2O5]/Δt 2 N2O5 (g) W 4 NO2 (g) + O2 (g)
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4/9/11 Chapter 13 – Examples Time (s) [N2O5] (mol/ L) 0 0.100 50 0.0707 100 0.0500 200 0.0250 300 0.0125 400 0.00625
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142 Ch 13 Kinetics - Chemistry 142 Chapter 13 Chemical...

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