Equilibrium Law Calculations(with RICE charts)Example 14.7 - pg. 567 H2+ I2↔2HIRICEH2I2HIRatio, Initial, Change, EquilibriumQ - Try PE 9 on pg. 568• Read 566 (from “Calculating Kc…”) to 568. Follow the sample calculation carefully. PE 9 - pg. 568 PCl3+ Cl2↔PCl5Q - Try 14.38, 14.39 pg. 58914.9 - pg. 570 CO + H2O ↔CO2+ H2COH2OCO21110.1000.1000-x-x+x0.10 - x 0.10 - xxRICEH210+xx= 4.06=[0.10 -x]2[x]2Kc =[CO2][H2][CO][H2O]x/[0.10-x] = 2.01, x = 0.201-2.01x, 3.01x = 0.201x=0.0668Read 570-1. Follow sample calculation carefully. PE 11, 14.40, 14.41 pg. 589 (notice [ ] for 14.41)Equilibrium calculations when Kc is very small• Thus far, problems have been designed so that the solution for x is straightforward• If the problems were not so carefully designed we might have to use quadratic equation (or calculus) to solve the problem.• If Kc is very large or very small we can use a
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This note was uploaded on 04/12/2011 for the course CHEM 1010 taught by Professor Marshall during the Spring '11 term at North Texas.