equilibrium-law

Equilibrium-law - Equilibrium Law Introduction to the Equilibrium law • Read 14.3 to PE1 2H 2(g O 2(g ↔ 2H 2 O(g Step 1:Set up the

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Equilibrium Law Introduction to the Equilibrium law • Read 14.3 to PE1 2H 2 (g) + O 2 (g) ↔ 2H 2 O (g) Step 1:Set up the “equilibrium law” equation Kc = Step 2:Product concentrations go in numerator [H 2 O] 2H 2 (g) + O 2 (g) ↔ 2 H 2 O (g) [H 2 O] 2 2H 2 (g) + O 2 (g) ↔ 2 H 2 O (g) Step 3:Concentration in mass action expression is raised to the coefficient of the product 2 H 2 (g) + O 2 (g) ↔ 2H 2 O (g) [H 2 ] 2 [O 2 ] Step 4:Reactant concentrations go in denominator Step 5:Concentrations in mass action expression are raised to the coefficients of reactants 2 H 2 (g) + O 2 (g) ↔ 2H 2 O (g) [H 2 ] 2 [O 2 ] Mass action expression Equilibrium constant Equilibrium law: important points • State (g, l, s, aq) may or may not be added at this point since we will only be dealing with gasses for this section. Later it will matter. • The equilibrium law includes concentrations of products and reactants in mol/L (M) • The value of Kc will depend on temperature, thus this is listed along with the Kc value...
View Full Document

This note was uploaded on 04/12/2011 for the course CHEM 1010 taught by Professor Marshall during the Spring '11 term at North Texas.

Page1 / 7

Equilibrium-law - Equilibrium Law Introduction to the Equilibrium law • Read 14.3 to PE1 2H 2(g O 2(g ↔ 2H 2 O(g Step 1:Set up the

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online