hess-lab-answers

hess-lab-answers - NaCl(aq) + H 2 O 6. 1. Definition of...

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Heats of reaction NaOH(s) NaOH(aq) H= -43 .5 kJ NaOH(s) + HCl(aq) NaCl(aq) + H 2 O H= -97.0 kJ NaOH(aq) + HCl(aq) NaCl(aq) + H 2 O H= -50 .2 Mol NaOH 0.1 0.1 0.1 Mol HCl 0 0.1 0.1 H = cm T =(4.18)(200)( T) T= 5.2 43 47 J T= 11.6 969 8 J T= 6.0 50 16 J 1. NaOH dissolves (goes from solid to aqueous) 2. NaOH dissolves and there is a reaction (neutralization) between NaOH and HCl 3. The reaction between NaOH and HCl
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7. NaOH(s) NaOH(aq) H= -43 .5 kJ NaOH(aq) + HCl(aq) NaCl(aq) + H 2 O H= -50.2 kJ NaOH(s) + HCl(aq) NaOH(aq) + HCl(aq) NaCl(aq) + H 2 O(l) NaOH(s) + HCl(aq)
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Unformatted text preview: NaCl(aq) + H 2 O 6. 1. Definition of Hesss law: for any reaction that can be written in steps, H is equal to the sum of the H s for the individual steps 8. E.g. the NaOH(s) takes some time to dissolve allowing heat to escape and perhaps giving artificially low values for changes in temp. E.g. the calorimeter is not perfectly insulated, thus larger jumps in temperature would not show up as high as they should For more lessons, visit www.chalkbored.com...
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This note was uploaded on 04/12/2011 for the course CHEM 1010 taught by Professor Marshall during the Spring '11 term at North Texas.

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hess-lab-answers - NaCl(aq) + H 2 O 6. 1. Definition of...

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