titration-answers

titration-answers - AcidBase AcidBase Titration Prelab...

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Acid – Base  Acid – Base  Titration Titration
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Prelab question Prelab question M A x #H x V A = M B x #OH x V B M A = 6 M, #H = 2, V A = ? M B = 0.5 M, #OH = 1, V B = 0.5 L (6 M)(2)(V A ) = (0.5 M)(1)(0.5 L) V A = (0.5 M)(1)(0.5 L) / (6 M)(2) V A = 0.25 mol / 12 M = 0.0208 L = 2 0.8 mL
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Typical results from experiment Typical results from experiment Lab results - titration of NaOH with HCl 0 2 4 6 8 10 12 14 0 10 20 30 40 50 Amount of HCl added pH
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Calculations (0 – 25) Calculations (0 – 25) 0 10 15 20 23 24 25 c vol (L) d HCl mol e NaOH f Net HCl g [OH ] h pOH i [H+] j pH 0.025 0 .0050 0.200 0.70 13.3 0.035 .0020 .0030 0.086 1.067 12.9 0.040 .0030 .0020 0.050 1.301 12.7 0.045 .0040 .0010 0.022 1.653 12.3 0.048 .0046 .0004 0.008 2.079 11.9 0.049 .0048 .0002 0.004 2.389 11.6 0.050 .0050 0 0 0 7 0 7
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Calculations (25 – 50) Calculations (25 – 50) 25 26 27 30 35 40 50 c vol (L) d HCl mol e NaOH f Net HCl g [OH ] h pOH i [H+] j pH 0.050 .0050 0 0 0 7 0.051 .0052 .0002
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titration-answers - AcidBase AcidBase Titration Prelab...

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