PHY 2130 Homework solutions
Assignment 9
9.14
Let the weight of the car be
W
. Then, each tire supports
4
W
,
and the gauge pressure is
4
F
W
P
A
A
=
=
.
Thus,
(
29 (
29
2
5
4
4 0.024 m
2.0 10 Pa
W
A P
=
=
×
=
4
1.9 10 N
×
9.18
The needed gauge pressure is
0
gauge
P
P
P
gh
ρ
=

=
(
29
3
3
2
kg
m
1 m
10
9.80
1200 ft
m
s
3.281 ft
=
=
6
3.58 10 Pa
×
9.19
The density of the solution is
3
3
1.02
1.02 10 kg m
water
=
=
×
. The gauge pressure of
the fluid at the level of the needle must equal the gauge pressure in the vein, so
4
1.33 10 Pa
gauge
P
gh
=
=
×
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 Spring '11
 petrov
 Physics, Work, Kilogram, Equals sign, gauge pressure, Homework solutions Assignment

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