Assign12 - PHY 2130 Homework solutions Assignment 12 13.1...

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PHY 2130 Homework solutions Assignment 12 13.1 (a) The force exerted on the block by the spring is ( 29 ( 29 160  N m 0.15 m 24 N s F kx = - =- - = + , or s F = 24 N directed toward equilibrium position (b) From Newton's second law, the acceleration is 2 24 N m 60  0.40 kg s s F a m + = = = + = 2 m 60   toward equilibrium position s 13.15 From conservation of mechanical energy, ( 29 ( 29 g s g s f i KE PE PE KE PE PE + + = + + , we have 2 2 2 1 1 1 0 0 0 2 2 2 mv kx kA + + = + + , or ( 29 2 2 k v A x m = - (a) The speed is a maximum at the equilibrium position, x = 0. ( 29 ( 29 ( 29 2 2 19.6  N m 0.040 m 0.40 kg max k v A m = = = 0.28  m s (b) When 0.015 m x = - , ( 29 ( 29 ( 29 ( 29 2 2 19.6  N m 0.040 m 0.015 m 0.40 kg v = - - = 0.26  m s (c) When 0.015 m x = + , ( 29 ( 29 ( 29 ( 29 2 2 19.6  N m 0.040 m 0.015 m 0.40 kg v = - + = 0.26  m s
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(d) If 1 2 max v v = , then ( 29
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This note was uploaded on 04/12/2011 for the course PHYS 2130 taught by Professor Petrov during the Spring '11 term at Wayne State University.

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Assign12 - PHY 2130 Homework solutions Assignment 12 13.1...

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