Chemistry 1A - Spring 2009 - Nitsche - Midterm 3 Solutions

Chemistry 1A - Spring 2009 - Nitsche - Midterm 3 Solutions...

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Page 1 of 11 Chemistry 1A, Spring 2009 KEY Midterm 3 April 13, 2009 (90 min, closed book) Name:___________________ SID:_____________________ TA Name:________________ x There are 20 Multiple choice questions worth 3 points each. x There are 3, multi-part short answer questions. x For the multiple choice section, fill in the Scantron form AND circle your answer on the exam. x Put your written answers in the boxes provided. Full credit cannot be gained for answers outside the boxes provided. x The lecture, homework, chemquizzes, discussion or experiment that each question is based upon is listed after the question e.g. [L3, HW 1.13, CQ 7.3] Question Points Score Multiple Choice Section 60 Question 21, K and ǻ G 8 Question 22, Multiple K 13 Question 23abc, Haber 9 Question 23defg, Haber 10 Total 100
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Page 2 of 11 Thermodynamics: ' G q = ' H q Ͳ T ' S q ' H q = 6 ' H q f (products) Ͳ 6 ' H q f (reactants) ' S q = 6 S q (products) Ͳ 6 S q (reactants) ' G q = 6 ' G q f (products) Ͳ 6 ' G q f (reactants) S = k B lnW ' S = q rev /T ' E = q + w w = - P ext ' V for aA + bB cC + dD b a d c B A D C Q ] [ ] [ ] [ ] [ At equilibrium, Q = K ' G = ' G q + RTln Q G = G° + RTln(a); a = activity = Ȗ P/P° or Ȗ [A]/[A]° ' G q = Ͳ RTln K ' G q = Ͳ nF ' ȯ º ' ȯ = ' ȯ º - (RT/nF) lnQ R S T R H K q ' ± q ' ² 1 ln ¨ T = ik b,f m Ȇ = iMRT P total = P A + P B = X A P A ° + X B P B ° Acid Base: pH = - log[H 3 O + ] pX = Ͳ log X ] [ ] [ log HA A pK pH a ² ± Kinetics: [A] t = [A] 0 e -kt ln[A] t = ln[A] 0 ± kt Quantum: E = h Q OQ = c O deBroglie = h / p = h / mv E kin (e-) = h Q - ) = h Q - h Q 0 f ² R n Z E n 2 2 ¨ x ¨ p ~ h p = mv Particle in a box (1-D Quantum): E n = h 2 n 2 /8mL 2 ; n = 1, 2, 3. .. Vibrational: E v = (v + ½) hA/2 ʌ ; A =(k/m) ½ Rotational: E n = n(n + 1) hB; B = h/8 ʌ 2 I; I = 2mr 2 m = m A m B /(m A + m B ) Ideal Gas: PV = nRT Constants: N 0 = 6.02214 x 10 23 mol -1 R f = 2.179874 x 10 -18 J R f = 3.28984 x 10 15 Hz k = 1.38066 x 10 -23 J K -1 h = 6.62608 x 10 -34 J s m e = 101939 x 10 -31 kg c = 2.99792 x 10 8 m s -1 T (K) = T (C) + 273.15 F = 96,485 C / mol 1 V = 1 J / C Gas Constant: R = 8.31451 J K -1 mol -1 R = 8.20578 x 10 -2 L atm K -1 mol -1 1 nm = 10 -9 m
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Page 3 of 11 M ULTIPLE C HOICE One mole each of gaseous He, CO 2 and NH 3 are placed in a sealed container. The volume of the container is initially 20 L and the temperature is 298K. 1) Which gas has the lowest kinetic energy? [CQ 20.1] A) He B) CO 2 C) NH 3 D ) t h e y a r e a l l t h e s a m e 2) Which gas has the most frequent number of collisions with the container walls? [HW 72] A) He B) CO 2 C) NH 3 D ) t h e y a r e a l l t h e s a m e 3) If the container volume was reduced to 50 mL, which of the gases is most likely to still behave ideally? [L 21] A) He B) CO 2 C) NH 3 D ) t h e y a r e a l l t h e s a m e 4) The valve on the container is opened and the gases expand adiabatically. The temperature of the gas _______ because ______? [CQ 23.1, HW 6.6] A) Increases, the gases are traveling faster B) Increases, the internal energy of the gas is increasing C) Stays the same, adiabatic means that temperature is constant D) Decreases, the system loses heat to the surroundings E) Decreases, the system does work 5) A 125.0 g piece of iron is heated to 400 C and placed in 300.0 g of water at 25 C. If the specific heat capacities of iron and water are 0.449 J/K±g and 4.184 J/K±g respectively, what will be the final temperature of the water?
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Chemistry 1A - Spring 2009 - Nitsche - Midterm 3 Solutions...

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