{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Stats II week 1

# Stats II week 1 - Sarah Anderson Stats II week 1 The...

This preview shows pages 1–2. Sign up to view the full content.

Sarah Anderson Stats II week 1 The following Exercises from Chapter 7: (10 points) Exercise 4 (page 223) Exercises 10, 12 (page 229) Exercises 15, 16 (page 233) Exercises 20, 22 (page 235) Exercises 24, 28 (page 237) Exercise 32 (page 241) 4.) a. 400+3800/2 = 2100 b. sq root of (3800-400)^2/12 = 981.49 or 981.5 c. 1/b-a =f(x) for uniform dist. so. .1/3400 =.47 = p d. 1/3400 dx = .235 = p 10.) a. p (55<x<65) → p 55-60/5<z< 65-60/5 p(-1<z<1) TI83: normcdf (55, 65,60, 5) = approx. .68 on a table z table table P (0<z<1) = .34 so just dbl it, b. normcdf (50,70, 60, 5) = approx. .95 c. normcdf (45,75,60,5) = approx. .99 What is being demonstrated here is Chebyshev's Rule concerning the proportion of population lying within the 1,2,3 standard deviations from the mean. 12.) μ = 90 σ = 22 standardize x to z = (x - μ) / σ P(x > 75) = P( z > (75-90) / 22) = P(z > -0.6818) = 0.7517 (From Normal probability table) μ = 90 σ = 22 standardize x to z = (x - μ) / σ P(x > 100) = P( z > (100-90) / 22)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 4

Stats II week 1 - Sarah Anderson Stats II week 1 The...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online