STATS WEEK 3

# STATS WEEK 3 - 18 15 15 31 33 39 41 54 a mode is 15 because...

This preview shows page 1. Sign up to view the full content.

Sarah Anderson Statistics 1 Week 3 (4,8,16,18,20 done so far ) 25,32,36,46,50,54,60 4.) a. Compute the mean of the following sample values: 1.3, 7.0, 3.6, 4.1, 5.0 1.3 + 7.0 + 3.6 + 4.1 + 5.0 = 21/5 = 4.2 b. Show that Σ (X-X)= 0: (1.3 – 4.2) + (7 – 4.2) + (3.6 – 4.2) + (4.1 – 4.2) + (5.0 – 4.2) = 0 8.) a. 14+24+19+31+36+26+17 = 167. 167/7 = 23.86 b. Statistic since it only indicates the first 7 days of the month. 16.)750 + 1000 + 4000 = 5,750. 5750/amount of hours(40) = 5750/40 = 143.75
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 18.) 15, 15, 31, 33, 39, 41, 54 a. mode: is 15 because it occurs the most frequently b. median: 33 c. mean: 15+15+31+33+39+41+54 = 228. 228/7= 32.57 20.) 6, 8, 8, 8, 10, 11, 12, 14, 17, 17 a. mode: 8 is the mode, occurs most frequently b. median: 10.5 c. mean: 111/10 = 11.1 25.) a. X= 90.4 12 = 7.53 b. Median= 7.45. There are several modes: 6.5, 7.3,7.8, and 8.7 c. X= 33.8 4 =8.45, median = 8.7 About 1 percent point higher in Winter...
View Full Document

## This note was uploaded on 04/12/2011 for the course STAT 2610 taught by Professor Sanjeev during the Spring '11 term at Bemidji State.

Ask a homework question - tutors are online