Stats week 6 - Sarah Anderson Stats Week 6 Exercise 4(page...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Sarah Anderson Stats Week 6 Exercise 4 (page 223) done Exercises 10, 12 (page 229) done Exercises 15, done 16 (page 233) done Exercises 20, 22 (page 235) done Exercises 24, 28 (page 237) done Exercise 32 (page 241) done 4.) a. 400+3800/2 = 2100 b. sq root of (3800-400)^2/12 = 981.49 or 981.5 c. 1/b-a =f(x) for uniform dist. so. .1/3400 =.47 = p d. 1/3400 dx = .235 = p 10.) a. p (55<x<65) → p 55-60/5<z< 65-60/5 p(-1<z<1) TI83: normcdf (55, 65,60, 5) = approx. .68 on a table z table table P (0<z<1) = .34 so just dbl it, b. normcdf (50,70, 60, 5) = approx. .95 c. normcdf (45,75,60,5) = approx. .99 What is being demonstrated here is Chebyshev's Rule concerning the proportion of population lying within the 1,2,3 standard deviations from the mean. 12.) μ = 90 σ = 22 standardize x to z = (x - μ) / σ P(x > 75) = P( z > (75-90) / 22) = P(z > -0.6818) = 0.7517 (From Normal probability table) μ = 90 σ = 22 standardize x to z = (x - μ) / σ P(x > 100) = P( z > (100-90) / 22) = P(z > 0.4545) = 0.3264
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 4

Stats week 6 - Sarah Anderson Stats Week 6 Exercise 4(page...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online