stats week 9 NOT DONE

stats week 9 NOT DONE - Sarah Anderson Stats week 9...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Sarah Anderson Stats week 9 Exercises 18 (page 348) Exercise 22 (page 352) Exercise 28 (page 355) 2.) Standard error of Mean = Standard deviation / sq rt n = 3 / sq rt 36 = 3 /6 = 0.5 (O-E) / S.E = (12 -10) / 0.5 = 4 Critical value at .02 level of significance = 2.33 Since the calculated value (4) is greater than the critical value (2.33) the Null hypothesis will be rejected. 4.) Standard error of Mean = Standard deviation / sq rt n S.D = 15 and n = 64 S.E of Mean = 15/sq rt 64 = 1.875 I think in case of Ho Mu is >/= 210 (O-E)/S.E = (215 - 210) / 1.875 = 2.67 Critical value at .03 significance level = 2.17 Since the calculated value (2.67) is > the critical value (2.17) the null hypothesis will be rejected. 6.) H0 : µ = 3 (that is what it should be) H1 : µ < 3 (because we believe it is lower) (this is a one sided test) What we do next is to calculate the p-value that belongs to our sample. The p-value gives us the probability that we would have measured the outcome in our sample if H0 is TRUE. Or in other words, the p-value gives the probability that Ho is true.
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern