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GPII - Homework 3, Electric Current - solutions

# GPII - Homework 3, Electric Current - solutions -...

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Unformatted text preview: honea (cth632) – H3ElectricCurrrent – avram – (1956) 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points In a particular television picture tube, the measured beam current is 94 . 9 μ A. How many electrons strike the tube screen every 26 s? Correct answer: 1 . 5402 × 10 16 electrons. Explanation: Let : I = 94 . 9 μ A = 9 . 49 × 10 − 5 C / s and Δ t = 26 s . The current is I = q Δ t = n q e Δ t . Thus n = I Δ t q e = (9 . 49 × 10 − 5 C / s) (26 s) 1 . 602 × 10 − 19 C / electron = 1 . 5402 × 10 16 electrons . 002 10.0 points A wire is made of a material with a resistiv- ity of 1 . 63303 × 10 − 8 Ω · m. It has length 6 . 72317 m and diameter 0 . 79857 mm. What is the resistance of the wire? Correct answer: 0 . 219206 Ω. Explanation: Let : ρ = 1 . 63303 × 10 − 8 Ω · m , ℓ = 6 . 72317 m , and r = 0 . 399285 mm = 0 . 000399285 m . By definition, the resistance of the wire is R = ρ ℓ A = ρ ℓ π r 2 = ( 1 . 63303 × 10 − 8 Ω · m ) (6 . 72317 m) π (0 . 000399285 m) 2 = . 219206 Ω . 003 (part 1 of 2) 10.0 points The potential difference in a simple circuit is 15 V and the resistance is 20 Ω....
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GPII - Homework 3, Electric Current - solutions -...

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