GPII - Homework 7, EM Waves - solutions

# GPII - Homework 7, EM Waves - solutions - honea(cth632 –...

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Unformatted text preview: honea (cth632) – H7ElMagnWave – avram – (1956) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points If the frequency of an electromagnetic wave is 1 × 10 6 Hz what is the wavelength? Correct answer: 3 × 10 11 nm. Explanation: λ = c f = 3 × 10 8 m / s 1 × 10 6 Hz = 300 m = 3 × 10 11 nm 002 (part 2 of 2) 10.0 points What type of electromagnetic wave is this? 1. X-rays 2. infrared 3. microwave 4. ultraviolet 5. visible light 6. radio wave correct 7. gamma rays Explanation: 003 (part 1 of 2) 10.0 points The magnetic field amplitude of an electro- magnetic wave is 5 . 2 × 10- 6 T. The speed of light is 2 . 99792 × 10 8 m / s . Calculate the amplitude of the electric field if the wave is traveling in free space. Correct answer: 1558 . 92 N / C. Explanation: Let : c = 2 . 99792 × 10 8 m / s and B = 5 . 2 × 10- 6 T . According to Maxwell’s equations for an electromagnetic wave in vacuum the relation between the amplitude of the magnetic field and the amplitude of the electric field must be E = c B = (2 . 99792 × 10 8 m / s) (5 . 2 × 10- 6 T) = 1558 . 92 N / C ....
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GPII - Homework 7, EM Waves - solutions - honea(cth632 –...

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