13-54-13-62 - 13.54 AnswerDetails = Fy= Solve for N. Cancel...

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13.54 Answer Details = Fy= Solve for N. Cancel m. associate the terms. Solve for v. Now. this is v MAXIMUM. I know, I know, I should learn to read theproblem. But this is an easy fix. Switch the signs in the numerator anddenominator to get vminimum: = So do that and get. 39.0 m/s Check my numbers; these big fractions tend to have calculationerrors. However, the formula is right! Newton's second law: F=ma First draw the free body diagram: There are four forces acting on the car, I will assignvariables as follows: W = force due to the weight of the car (acts at center of carstraight down) N = normal force from road reacting to the car (acts up onbottom of car perpendicular to road) A = normal force due to the centripetal motion (acts at centerof car parallel to horizontal 0 deg)
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F = force of friction (acts at bottom of car parallel toroad) Now equate a formula for each: W = ma = (1700kg)(9.81m/s 2 ) = 16677 N A = (m*v 2 ) / ρ = (1700kg * v 2 ) /100m = 17 v 2 N = N F = μ s N
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This note was uploaded on 04/12/2011 for the course CHEM 112 taught by Professor X during the Spring '06 term at Passaic County Community College.

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13-54-13-62 - 13.54 AnswerDetails = Fy= Solve for N. Cancel...

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