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Unformatted text preview: 4-1 F corresponds to the charge passed to deposit one mole of monovalent element at a cathode. As one mole contains Avogadro’s number of atoms, e=96 500 C6.02"1023=1.60"10#19C. 4-2 (a) Total charge passed =i*t=1.00 A( )3600 s( ) =3 600 C. This is 3 600 C1.60"10#19C=2.25"1022electrons. As the valence of the copper ion is two, two electrons are required to deposit each ion as a neutral atom on the cathode. The number of Cu atoms =number of electrons2=1.125"1022Cuatoms. (b) So the weight (mass) of a Cu atom is: 1.185 g1.125"1022atoms=1.05"10#22g. (c) m=qmolar weight96 5002( )or molar weight=m96 500( )2q=1.185 g( )96 500 C( )23 600 C=63.53 g. 4-3 Thomson’s device will work for positive and negative particles, so we may apply qm"V#B2ld. (a) qm"V#B2ld=2 000 V( )0.20 radians4.57$10%2T( )20.10 m( )0.02 m( ) =9.58$107C kg(b) As the particle is attracted by the negative plate, it carries a positive charge and is a proton....
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