# tut6_sol - 1 EE4210 Solution to Tutorial 6 Hopfield Network...

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Unformatted text preview: 1 EE4210 Solution to Tutorial 6 Hopfield Network ξ 1 = [-1, 1, -1, 1] T ξ 2 = [-1, 1, 1, -1] T ξ 3 = [1, - 1, 1, -1] T 1. ∑ =- = p T N p N W 1 1 μ μ μ ξ ξ I p =3, N =4 =            -------- 3 1 1 3 1 1 1 1 3 1 1 3 4 1 2. Condition for stability: ) sgn( i i W ξ ξ = for i = 1, 2, 3 (i) i = 1 1 1 1 1 1 1 5 5 5 5 4 1 sgn ) sgn( ξ ξ =            -- =                          -- = W (ii) i = 2 2 2 1 1 1 1 1 1 1 1 4 1 sgn ) sgn( ξ ξ =            -- =                          -- = W (iii) i = 3 3 3 1 1 1 1 5 5 5 5 4 1 sgn ) sgn( ξ ξ =            -- =                          -- = W b The three fundamental memories all satisfy the condition for stability. The three fundamental memories all satisfy the condition for stability....
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## This note was uploaded on 04/14/2011 for the course EE 4210 taught by Professor Wong during the Spring '10 term at City University of Hong Kong.

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tut6_sol - 1 EE4210 Solution to Tutorial 6 Hopfield Network...

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