tarea materuiales - a=2r = c 23 x4r = ×( )× ( / × × ×...

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Tarea n°1 Asignatura: Ciencia de Materiales Profesor: Miguel Eulufi Alumna: Anyenett Bachmann Yañez Calcular el factor de empaquetamiento para una estructura hexagonal compacta, espacio disponible y espacio ocupado. Solución: = Factor empaquetamiento N ° × atomos en la celda unidad Volumen de los atomos en la celda unitariaVolumen de la celda unitaria En la estructura Hexagonal compacta:
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Unformatted text preview: a=2r = c 23 x4r = ×( )× ( / × × × = ×( )× ( / × ×( ) × × = ×( )× FE 6 43 πr3 3 2 3 a2 c 6 43 πr3 3 2 3 2r 2 23 4r 6 43 ( / × × ×( )= = . πr3 3 2 3 23 16r3 π18 0 74 El espacio disponible es : (3x(√3)x(2r) 2 x (√2)x4r)/(2√3) - (6x4xπxr 3 )/3= 33,941 r 3- 25,1327r 3 = 8,808 r 3 El espacio ocupado es: (6x4xπxr 3 )/3...
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This note was uploaded on 04/13/2011 for the course INGEENERIN 100 taught by Professor Xx during the Fall '11 term at Universidad de Concepción.

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tarea materuiales - a=2r = c 23 x4r = ×( )× ( / × × ×...

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