exam01_f10 - 1 MASSACHUSETTS INSTITUTE OF TECHNOLOGY...

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Unformatted text preview: 1 MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics 8.01 Physics I Fall Term 2010 Exam 1: Equation Summary One-Dimensional Kinematics: , d d dt dt = = r v v a ! ! ! ! v x ( t ) ! v x , 0 = a x ( " t ) d " t " t = " t = t # , x ( t ) ! x = v x ( " t ) d " t " t = " t = t # Initial conditions : x and v x ,0 are the values at t = . Kinematics of Circular Motion for Circle of Radius R : Angular velocity: ! = d " dt ; Velocity: ˆ = v v ! ! ! Tangential component of velocity: v ! = R " Angular acceleration: ! = d " dt = d 2 # dt 2 Acceleration for circular motion: ˆ ˆ r a a ! = + a r ! ! Radial component of acceleration: a r = ! R " 2 Tangential component of acceleration: a ¡ = R ¢ Newton’s Second Law: Force, Mass, Acceleration: ! F = m ! A Newton’s Third Law: 1,2 2,1 = ! F F ! ! MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department 8.01 Physics I Fall Term 2010 Exam 1 Name Section Table and Group With the exception of Problem 1, answers without work shown will not be given any credit. Comments on how you are approaching the problem and what you are doing at any given point will be helpful to the grader in awarding partial credit, as will carefully drawn free body diagrams when appropriate. Problem 1 (20 points) Problem 2 (25 points) Problem 3 (30 points) Problem 4 (25 points) Total (100 points) 1 Problem 1a (5 points) You are standing by a window and see a ball (thrown from below) moving up past the window. The ball is visible for a time interval Δ t up . On its way down the ball is visible for a time interval Δ t down . Neglecting the effects of air resistance, how do Δ....
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exam01_f10 - 1 MASSACHUSETTS INSTITUTE OF TECHNOLOGY...

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