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hw 14 - brown(twb493 hw 14 turner(57340 This print-out...

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brown (twb493) – hw 14 – turner – (57340) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001(part1of3)10.0points A 6 . 3 kg particle moves along the x axis under the influence of a single conservative force. If the work done on the particle is 42 J as it moves from x 1 = 1 . 8 m to x 2 = 3 . 8 m, find the change in its kinetic energy. Correct answer: 42 J. Explanation: The change in the kinetic energy is equal to the work done: Δ K = W = 42 J . 002(part2of3)10.0points Find the change in its potential energy. Correct answer: - 42 J. Explanation: Since Δ K + Δ U = 0 , then Δ U = - Δ K = - 42 J . 003(part3of3)10.0points Find its speed at x 2 = 3 . 8 m if it starts from rest. Correct answer: 3 . 65148 m / s. Explanation: Using K = m ( v 2 end - v 2 init ) 2 we obtain v = radicalbigg K m = radicalBigg 2(42 J) 6 . 3 kg = 3 . 65148 m / s . 004 10.0points A block of mass m slides on a horizontal frictionless table with an initial speed v 0 . It then compresses a spring of force constant k and is brought to rest. v m k m μ = 0 How much is the spring compressed x from its natural length? 1. x = v 0 k g m 2. x = v 0 m g k 3. x = v 0 m k g 4. x = v 2 0 2 m 5. x = v 0 m k g 6. x = v 0 radicalbigg k m 7. x = v 2 0 2 g 8. x = v 0 radicalbigg m k correct 9. x = v 0 radicalBigg k m g 10. x = v 0 radicalbigg m g k Explanation: Total energy is conserved (no friction). The spring is compressed by a distance x from its natural length, so 1 2 m v 2 0 = E i = E f = 1 2 k x 2 , or x 2 = m k v 2 0 , therefore x = v 0 radicalbigg m k .
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