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Unformatted text preview: Version 084/ABBBA inclasstest 02 turner (57340) 1 This print-out should have 2 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A coin is placed 32 cm from the center of a horizontal turntable, initially at rest. The turntable then begins to rotate. When the speed of the coin is 110 cm / s (rotating at a constant rate), the coin just begins to slip. The acceleration of gravity is 980 cm / s 2 . What is the coefficient of static friction be- tween the coin and the turntable? 1. 0.594652 2. 0.432173 3. 0.408163 4. 0.398288 5. 0.492711 6. 0.385842 7. 0.363145 8. 0.474882 9. 0.318878 10. 0.524781 Correct answer: 0 . 385842. Explanation: The normal force on the coin is N = mg . The force provided by friction immediately before slippage is given by f = N = mg . At this moment the centripetal acceleration (there is no tangential acceleration) provides a force F = mv 2 r ....
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- Spring '08