{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw2solution

# hw2solution - Assignment 2 Math 427K Due Wednesday February...

This preview shows pages 1–5. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Assignment 2 Math 427K Due Wednesday, February 3, 20010 To obtain full credit, you must show all your work. Your assignments will not be accepted unless they are legible, neat, and stapled. Problem 1. Solve problems 13 to 20 from Chapter 2, Section 1 of the course textbook. Problem 2. Use separation of variables to ﬁnd the general solution. Then, obtain the particular solution satisfying the given initial condition. a) y’ — 33026—11 2 0, y(0) = 0 b) y’ = (312 — y) 6". 11(0) = 2 C) y’ = 6“”, y(0) =1 d) y’ = y(y — 2), y(0) = 4 Problem 3. Show that equation is exact and obtain its general solution. Also, ﬁnd the particular solution corresponding to the given initial condition. a) (sin(a:y) + xycos(my))dx + x2 cos(:cy) dy = 0, y(2) = —1 b) (3 x2 sin(2y) — 2:1: y) d2: + (2363 cos(2y) — x2) dy = 0, y(1/2) = 3.1 c) 3x2 y ln(y) d2: + (m3 ln(y) + m3 — 2 y) dy = 0, 111(8) = 3 d) 3dx —dy= 0, y(0) = 6 Problem 4. (Euler’s Method.) Use the Euler method to compute, by hand, y1, 312 and 313 for the speciﬁed initial value problem using h = 0.2. a) y’ = ~21. y(0) = 1 b) y' 2 1+ 237112, y(1) = —2 C) y’ = :82 — :12, y(3) = 5 d) y’ = tan(a: + 31), y(1) = 2 e)y’=x/?v’+_, y(0)=3 WW3) : 3 9/4! q; 'f 73%?) ”73) , N = 43%} Wkly 9?] {D L’(j);«>3 2:) N7 =v7vrc ,3 JL’XJ) “(33193 »J ’l 4WL ”3(8) 5 , M 1”“ g!) S}? — a} C C; t§5é}~§——7 Mink 4% \$0M“ ‘3 ...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern