{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

10 - Lecture 10 Stability Tests Motivating Examples...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
1 Lecture 10: Stability Tests Motivating Examples Stability of Close-Loop Systems Routh- Hurwitz’s Stability Criterion Jury’s Stability Test Reading: Chapter 7.1-7.5 A Motivating Example C ( s ) K s ( s +1) R ( s ) + ¡ T 1 ¡ e ¡ T s s G ( z ) = K ( e ¡ T + T ¡ 1) z +(1 ¡ e ¡ T ¡ Te ¡ T ) ( z ¡ 1)( z ¡ e ¡ T ) System is of type one. Hence the steady state error for tracking unit step input is 0, and the steady state error for tracking unit ramp input is e ss = T K dc = T KT = 1 K Let T =1; K =1. Then e ss = 1 0 2 4 6 8 10 12 14 16 0 2 4 6 8 10 12 14 16 Closed-loop poles: p 1 ; 2 = 0 : 5 § j 0 : 618
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon