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with
n
+ 1. That is,
f
1
=
nv
/2
L
is the lower frequency and
f
2
= (
n
+ 1)
v
/2
L
is the higher.
The ratio of the frequencies is
2
1
1
.
fn
f
n
+
=
The solution for
n
is
1
21
315 Hz
3.
420 Hz 315 Hz
f
n
ff
==
=
−−
The lowest possible resonant frequency is
f
=
v
/2
L
=
f
1
/
n
= (315 Hz)/3 = 105 Hz.
(b) The longest possible wavelength is
λ
= 2
L
. If
f
is the lowest possible frequency then
v
=
λ
f
= 2
Lf
= 2(0.75 m)(105 Hz) = 158 m/s.
47. (a) The resonant wavelengths are given by
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This note was uploaded on 04/16/2011 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.
 Spring '09
 NAJAFZADEH
 mechanics

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