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and
=
v
Lf
L
λ=
.
(a) Comparing the given function with Eq. 1660, we obtain
k
=
π
/2 and
ω
= 12
π
rad/s.
Since
k
= 2
π
/
λ
then
2
4.0m
4.0m.
2
L
ππ
=
¡
¡
=
λ
(b) Since
= 2
π
f
then 2
12 rad/s,
f
π= π
which yields
6.0Hz
24m/s.
fv
f
=
¡
=λ
=
(c) Using Eq. 16–26, we have
200 N
24 m/s
/(4.0 m)
v
m
τ
μ
=
¡
=
which leads to
m
= 1.4 kg.
(d) With
33
(
2
4
m
/
s
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This note was uploaded on 04/16/2011 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.
 Spring '09
 NAJAFZADEH
 mechanics

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